Question

已知丨x+y-1丨+(x-y+3)²=0,求实数x,y的值

Answer 1

已知丨x+y-1丨+(x-y+3)²=0

则丨x+y-1丨=0,(x-y+3)²=0

x+y=1,x-y=-3

解方程组

x=-1

y=2