Question

(x+y分之x加x+y分之2y)乘x+2y分之xy除(x分之1加y分之1)等于?

Answer 1

原式=[(x+2y)/(x+y)]×[xy/(x+2y)]÷[(x+y)/xy]

=[(x+2y)/(x+y)]×[xy/(x+2y)]×[xy/(x+y)]

=x²y²(x+2y)/[(x+y)²(x+2y)]

=x²y²/(x+y)²