Question

已知x^m=8,x^n=4,求x^2n-m和x^3n+2m.

Answer 1

x^(2n-m)

=x^2n/x^m

=(x^n)^2/x^m

=4^2/8

=16/8

=2

x^(3n+2m)

=x^3n*x^2m

=(x^n)^3*(x^m)^2

=4^3*8^2

=64*64

=4096