Question

1/x-4=3/x²-16和2/x+3-3/2=7/2x-6z怎么做

Answer 1

1/(x-4)=3/(x²-16)

两边同时×（x²-16）得

x+4=3

x=-1

经检验x=-1是原方程的根

2/(x+3)+3/2=7/（2x-6)

两边同时×2(x+3)(x-3)得

4(x-3)+3(x+3)(x-3)=7(x+3)

4x-12+3x²-27=7x+21

3x²-3x-60=0

x²-x-20=0

(x-5)(x+4)=0

x=5 x=-4

经检验x=5,x=-4是原方程的根