sin(2x+π/3 )=cos(2x+π/3-π/2)=cos(2x-π/6)
函数cos(2x+ ψ)(-π<ψ<π)的图像向右平移π/2 个单位后,解析式为
cos【2(x-π/2)+ ψ】=cos(2x-π+ψ)
-π+ψ=-π/6
ψ=5π/6
逆推法
sin(2x+π/3 )=cos(2x+π/3-π/2)=cos(2x-π/6)
函数cos(2x+ ψ)(-π<ψ<π)的图像向右平移π/2 个单位后,解析式为
cos【2(x-π/2)+ ψ】=cos(2x-π+ψ)
-π+ψ=-π/6
ψ=5π/6
逆推法