Question

计算2的4m-1次方乘以16乘以8的m-1次方+（-4）的2m次方乘以8的m次方（m为正整数）

Answer 1

原式=2^(4m-1)*2^4*(2^3)^(m-1)+(-2^2)^(2m)*(2^3)^m

=2^(4m-1+4)*2^(3m-3)+2^(2*2m)*2^(3m)

=2^(4m+3+3m-3)+2^(4m+3m)

=2^(7m)+2^(7m)

=2*2^(7m)

=2^(7m+1)