Question

X的平方+X+1=0,求X的2014次方+X的2012次方+1的值

Answer 1

x²+x+1=0

（x-1）（x²+x+1）=0

x^3 -1=0

x^3=1

x^2014+x^2012+1

=[(x^3)^671]*x+[(x^3)^670]*x^2+1

=x+x^2+1

=0