有理数的混合运算 整式的加减 一元一次方程 的计算题各36个

1个回答

  • 14.59+x-25.31=0

    x=10.72

    x-48.32+78.51=80

    x=49.81

    820-16x=45.5×8

    x=28.5

    (x-6)×7=2x

    x=8.4

    3x+x=18

    X=4.5

    0.8x+2.2=6.6

    x= 11

    12.5-3x=6.5

    x=2

    1.2(x-0.64)=0.54

    x=1.09

    x+12.5=3.5x

    x=5

    8x-22.8=1.2

    x=3

    :-9÷27/4×(-7)+4-4×(+4/3)

    原式= 9×4/27×7+4-4×4/3

    =4/3×7-4×4/3+4

    =(7-4)×4/3+4

    =4+4

    =8

    22/7×(22/7-22/3)×7/22÷22/21

    原式=22/7×(22/7-22/3)×7/22×21/22

    =22/7×7/22×(22/7-22/3)×21/22

    =22/7×21/22-22/3×21/22

    =3-7

    =-4

    (-1)^2011÷1/15+(-1/5)×(-5)^3

    原式=(-1)÷1/15+(-1/5)×(-125)

    =(-1)×15+1/5×125

    = -15+25

    =10

    -12^56×[(-1)^1999-22/3×(9/22-6/11)]

    原式=-12^56×[(-1)^1999-(22/3×9/22-22/3×6/11)]

    =-12^56×[(-1)^1999-(3-4)]

    =-12^56×(-1+1)

    =0

    1、3ab-5ab2+3a2b-4ab+2ab2-3ab

    原式=(3ab-3ab)-4ab+(-5ab2+2ab2)+3a2b

    =-4ab+(-5+2)ab2+3a2b

    =-4ab+(-3)ab2+3a2b

    =-4ab-3ab2+3a2b

    2、2(2x-y)-3(2x-y)2+2x-y-5(2x-y)2

    原式=2(2x-y)-3(2x-y)2+(2x-y)-5(2x-y)2

    =[2(2x-y)+(2x-y)]+[-3(2x-y)2-5(2x-y)2]

    =(2+1)(2x-y)+(-3-5)(2x-y)2

    =3(2x-y)-8(2x-y)2

    1、化简

    (1) (2a+b)-(a-2b)

    原式=2a+b-a+2b

    =2a-a+b+2b

    =(2-1)a+(1+2)b

    =a+3b

    (2) -3(a-2b)-2(2a-b)

    原式=-3a+(-3)(-2b)+(-2)(2a)+(-2)(-b)

    =-3a+6b-4a+2b

    =(-3-4)a+(6+2)b

    =-7a+8b

    (3) -1/4(-4a+4b/3)-1/3(3a-2b)

    原式=-[1/4•(-4a)+1/4•4b/3]-(1/3•3a-1/3•2b)

    =-(-a+b/3)-(a-2b/3)

    =a-b/3-a+2b/3

    =(a-a)+(-1/3+2/3)b

    =b/3

    (4) 3x2y-2[3x2y-3(3xyz+2x2z)+x2z]-3xyz

    原式=3x2y-2[3x2y-(9xyz+6x2z)+x2z]-3xyz

    =3x2y-2(3x2y-9xyz-6x2z+x2z)-3xyz

    =3x2y-2[3x2y-9xyz+(-6x2z+x2z)]-3xyz

    =3x2y-2(3x2y-9xyz-5x2z)-3xyz

    =3x2y-(6x2y-18xyz-10x2z)-3xyz

    =3x2y-6x2y+18xyz+10x2z-3xyz

    =-3 x2y+15xyz+10x2z

    2、若A=3x2y+4xy2,B=2xy2-x2y,求-2A-3B

    -2A-3B=-2(3x2y+4xy2)-3(2xy2-x2y)

    =-(6x2y+8xy2)-(6xy2-3x2y)

    =-6x2y-8xy2-6xy2+3x2y

    =(-6x2y+3x2y)+(-8xy2-6xy2)

    =-3x2y-14xy2

    3、先化简再求值:若|x+1|+(y-1/3)2=0,求8xy-2{xy+3[3x4y-2(x4y+2xy)+5xy]-2x4y}的值

    化简:原式=8xy-2{xy+3[3x4y-(2x4y+4xy)+5xy]-2x4y}

    =8xy-2[xy+3(3x4y-2x4y-4xy+5xy)-2x4y]

    =8xy-2[xy+3(x4y+xy)-2x4y]

    =8xy-2(xy+3x4y+3xy-2x4y)

    =8xy-2(4xy+x4y)

    =8xy-8xy-2x4y

    =-2x4y

    由|x+1|+(y-1/3)2=0,得

    x=-1,y=1/3

    将x=-1,y=1/3代入-2x4y,得

    -2×(-1)4×1/3=-2/3

    所以,原式=-2/3

    4、有一道题:求两个多项式的差.小刚错把2a2b-3ab2当作被减数,解得差为-a2b,求正确的差.

    设A=2a2b-3ab2,C=-a2b,另外一个多项式为B

    小刚列的式子为:A-B=C,所以B=A-C

    B=(2a2b-3ab2)-(-a2b)

    =2a2b-3ab2+a2b

    =3a2b-3ab2

    正确的差应为:

    B-A=(3a2b-3ab2)-(2a2b-3ab2)

    =3a2b-3ab2-2a2b+3ab2

    = a2b

    (别因为a-b与b-a是相反数,小刚将被减数和减数搞反了,所以得到的差是正确的差的相反数,因此,正确的差为-(-a2b)= a2b)