Question

已知x=-4,y=四分之一,则代数式x的2次方*x的2n次方*（y的n+1次方）的2次方=______

Answer 1

y=1/4=(-X)^(-1)

x^2*x^2n*[y^(n+1)]^2

=X^(2+2n)*(-X)^2(-n-1)

=X^(2+2n-2n-2)

=X^0

=1