设函数f(x,y)=x^2+y^2+ln(y/x),则f(kx,ky)=
1个回答
把x换成kx,把y换成ky
f(kx,ky) = k^2·x^2+k^2·y^2+ln(ky/kx)= k^2·x^2+k^2·y^2+ln(y/x).并且k不等于0
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