化简sin2(α+π/4)-sin2(π/4-α)

1个回答

化简：2cos²α-1/【2sin(π/4-α)sin²(π/4+α)】
化简 {sin(π+α)cos(α-2π)tan9π/4}/sin(-α)sin(7π/2+α)
化简：[1+2sin(α+2π)*cos(α-2π)]/[sin(α+4π)+cos(α+8π)]
化简：（1）cos(α+π)sin(−α)cos(−3π−α)sin(−α−4π)（2）cos(α−π2)sin(5π2
化简sin2α-2cos²α/sin（α-π/4）
化简cos2(π/4-α)-sin2(π/4-α)
化简[sin(π/2+α)*cos(π/2-α)]/cos(π+α)+[sin(π-α)*cos(π/2+α)]/sin
化简[sin(π/2-α）cos(π/2-α)]/cos(π+α)-[sin(π-α)cos(π/2-α)]/sin(π
化简(2cos²α-1)/[2tan(π/4-α)sin²(π/4+α)]
sin｛π－α｝cos｛2π－α｝tan｛－α＋π｝/sin｛π＋α｝化简