Question

/a-1/+（b-2）2次方=0,a=3a的2次方-6ab+b的2次方,b=-a的2次方-5,求a-b的值

Answer 1

|a-1|+(b-2)²=0

a-1=0 b-2=0

a=1 b=2

a-b

=3a²-6ab+b²-(-a²-5)

=4a²-6ab+b²+5

=4-2*6+2²+5

=4-12+4+5

=1