Question

若m等于它的倒数,求m-2分之m的平方+m-6除以m的平方-3m+1分之m+3的值

Answer 1

若m等于它的倒数

即m=1/m m²=1

m=±1

(m²+m-6)/(m-2)÷(m+3)/(m²-3m+1)

=[(m+3)(m-2)/(m-2)]*[(m²-3m+1)/(m+3)]

=m²-3m+1

=1-3m+1

=2-3m

=-1或5