(1)-(1/n)(1/(n+1))=-1/n+1/(n+1)
(2)
(-1×1/2)+(-1/2×1/2)+(-1/3×1/4)+…+(-1/2004×1/2005)
=-1+1/2+-1/2+1/3+-1/3+1/4+...+-1/2004+1/2005
中间项都是一正一负抵消
只剩头尾两项
=-1+1/2005
=-2004/2005
(1)-(1/n)(1/(n+1))=-1/n+1/(n+1)
(2)
(-1×1/2)+(-1/2×1/2)+(-1/3×1/4)+…+(-1/2004×1/2005)
=-1+1/2+-1/2+1/3+-1/3+1/4+...+-1/2004+1/2005
中间项都是一正一负抵消
只剩头尾两项
=-1+1/2005
=-2004/2005