(3x-7)/[(x-4)*(x-5)]=A/(x-4)+B/(x-5)
等式两边同乘(x-4)*(x-5)得
3x-7=A(x-5)+B(x-4)
3x-7=(A+B)x+(-5A-4B)
使等式左右两边对应的系数相等,即:
A+B=3
-5A-4B=-7
解得A=-5,B=8
(3x-7)/[(x-4)*(x-5)]=A/(x-4)+B/(x-5)
等式两边同乘(x-4)*(x-5)得
3x-7=A(x-5)+B(x-4)
3x-7=(A+B)x+(-5A-4B)
使等式左右两边对应的系数相等,即:
A+B=3
-5A-4B=-7
解得A=-5,B=8