这不就是简单的换元吗?因为u=u(x)；所以du=u'(x)dx=(du/dx)dx；
当x=t₁时,u₁=u(t₁)；当x=t₂时,u₂=u(t₂)；故
[t₁,t₂]∫u(x)u'(x)dx=[t₁,t₂]∫u(x)(du/dx)dx=[u(t₁),u(t₂)]∫u(x)du
请教∫u(x)(du/dx)dx [t1,t2]可以化简为∫udu [u(t1),u(t2)] 为什么?如何化简的,
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