(I)设P i为甲、乙、丙三人分别回答一道问题时答对的概率(i=1,2,3)
据题意得 P 1 =
3
4 , (I- p 1 )(1- p 3 )=
1
12
所以 P 3 =
2
3
又 P 2 P 3 =
1
4 所以 P 3 =
3
8
该单位代表队答对此题的概率1-(I-p 1)(1-P 2)(1-p 3)= 1-
1
4 ×
5
8 ×
1
3 =
91
96
(II)设该单位代表队答对的题目个数为ξ,得分为η则
ξ~B(10,
91
,96 )且η=20ξ-10(10-ξ)=30ξ-100
故Eη=30Eξ-100= 30×10×
91
96 -100 =
1475
8