(x²-√2x+1/3)²
=[(x²-√2x)+1/3]²
=(x²-√2x)²+2/3(x²-√2x)+1/9
=x^4-2√2x³+2x²+2x²/3-2√2x/3+1/9
=x^4-2√2x³+8x²/3-2√2x/3+1/9
简便计算(x²-√2x+1/3)²
(x²-√2x+1/3)²
=[(x²-√2x)+1/3]²
=(x²-√2x)²+2/3(x²-√2x)+1/9
=x^4-2√2x³+2x²+2x²/3-2√2x/3+1/9
=x^4-2√2x³+8x²/3-2√2x/3+1/9