4:原式=(4m-4n)^2-(5m+5n)^2
=(4m-4n+5m+5n)(4m-4n-5m-5n)
=-(9m+n)(9n+m)
5:令t=x^2-4x
则原式=t^2+8t+16
=(t+4)^2
所以原式=(x^2-4x+4)^2
6:令t=x^2-5 所以8(5-x^2)=-8(x^2-5)=-8t
则原式=t^2-8t+16
=(t-4)^2
所以原式=(x^2-5-4)^2
欢迎追问
4:原式=(4m-4n)^2-(5m+5n)^2
=(4m-4n+5m+5n)(4m-4n-5m-5n)
=-(9m+n)(9n+m)
5:令t=x^2-4x
则原式=t^2+8t+16
=(t+4)^2
所以原式=(x^2-4x+4)^2
6:令t=x^2-5 所以8(5-x^2)=-8(x^2-5)=-8t
则原式=t^2-8t+16
=(t-4)^2
所以原式=(x^2-5-4)^2
欢迎追问