Question

初一数学完全平方和平方差公式 2题

Answer 1

(2x+3y-5)(2x-3y+1)=[2(x-1)+3(y-1)][2(x-1)-3(y-1)]

=[2(x-1)]^2-[3(y-1)]^2=4(x-1)^2-9(y-1)^2

(2^2+1)(2^4+1)(2^8+1)..(2^32+1)=1/(2^2-1)*(2^2-1)(2^2+1)(2^4+1)(2^8+1)..(2^32+1)=1/3*(2^4-1)(2^4+1)(2^8+1)..(2^32+1)=.

=1/3*(2^64-1)