计算(x+y)^2-3(x+y)^3+3(y+x)^2-5(y+x)^3拜托求解
2个回答
原式=(x+y)^2-3(x+y)^3+3(x+y)^2-5(x+y)^3
=4(x+y)^2-8(x+y)^3
=4(x+y)^2*(1-2x-2y)
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