解题思路:首先将原式进行补项进而提取公因式得出即可.
原式=3x(2x-y-2)+3xy+6x+xy-2y2+2x-8y-8
=3x(2x-y-2)+4xy-2y2+8x-8y-8
=3x(2x-y-2)+2y(2x-y-2)+2y2+4y-2y2+8x-8y-8
=3x(2x-y-2)+2y(2x-y-2)+8x-4y-8
=3x(2x-y-2)+2y(2x-y-2)+4(2x-y-2)
=(2x-y-2)(3x+2y+4)
点评:
本题考点: 因式分解-分组分解法.
考点点评: 此题主要考查了分组分解法分解因式,正确进行拆项是解题关键.