2[10^(n+1)]^2*100*5^(2n)*

2[10^(n+1)]^2*100*5^(2n)*2^(2n-1)

2个回答

2[10^(n+1)]^2*100*5^(2n)*2^(2n-1)
=2*10^[2(n+1)]*100*5*5^(2n-1)*2^(2n-1)
=2*1000*10^(2n-1)]*100*5*5^(2n-1)*2^(2n-1)
=10^[2(2n-1)]^*10^6
=10^(4n+4)

(2)-(-10)^2n×100×(-10)^2n-1
根号下﹙1*2*3﹢2*4*6﹢……﹢n*2n*3n﹚／﹙1*5*10﹢2*10*20﹢……﹢n*5n*10n﹚
1+3+5+.+(2n-5)+(2n-3)+(2n-1)+(2n+1)+(2n+3)
归纳法求证1^2/(1*3)+2^2/(3*5)+...+n^2/(2n-1)(2n+1)=n(n+1)/[2(2n+1
两道数学题求教(-3)^n + 3(-3)^n-110^2n+1 + 10^2n-1 / 10^2n+1 - 10^2n
（-10）^2n=____ ；（-10）^2n+1=____；
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1/2-1/n+1＜1/2^2+1/3^2+……+1/n^2＜n-1/n(n=2,3,4,5,6.
-(-10)2nx100x(-10)2n-1=
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