Question

设M=｛x|x-2/3+x-3/2=3/x-2+2/x-3｝N={x|x-6/5+x-5/6=5/x-6+6/x-5}求

Answer 1

M=｛x|（x-2)/3+(x-3)/2=3/(x-2)+2/(x-3)｝方程（x-2)/3+(x-3)/2=3/(x-2)+2/(x-3）设(x-2)/3=t,(x-3)/2=s∴t+s=1/t+1/s=(t+s)/(ts)∴(t+s)[1-1/(ts)]=0∴t+s=0或ts=1若t+s=0,则(x-2)/3+(x-3)/2=0∴x=13/5若ts=1则（x...