求高手帮忙解一下积分1/(x^2+4)^(3/2 - 知识问答

求高手帮忙解一下积分1/(x^2+4)^(3/2)

2个回答

∫dx/(x^2+4)^(3/2)
设x=2tant,dx=2(sect)^2dt,代入得：
∫dx/(x^2+4)^(3/2)
=∫2(sect)^2dt/(2(sect)^3)
=∫costdt
=sint+C
=x/√(x^2+4)+C

相关问题