要用点除,改为y=(3*x.^2+4*x+4)./(x.^2+x+1);
这是我编的程序 x=-5:0.01:5;y=(3*x.^2+4*x+4)/(x.^2+x+1);plot(x,y) 为什
1个回答
相关问题
-
(3x+4y=2,2x-y=5)(y=1-x,x-2y=4)(y=三分之二 x,3x=2y+1)(5x-2y-4=0,x
-
(3x-y)^2-(2x+y)^2-5x(x-y),其中x=0.2,y=0.01
-
(1)﹛2x-y=5 (2) 4x-y=1 (3)5x+y=2 7x-3y=20 y=2x+3 x-3y=4 (4)3x
-
2X=3Y,4x-5y=2 -6x+5y=3,3x=4y 2x+3y=5,3x=y-9 3x=1-y,3x=2y-5
-
①﹙2x+5﹚/﹙3x-6﹚+﹙4-5x﹚/﹙2x-4﹚=0②若2x²-3xy+y²=0求x/y+y
-
(1)x-y=3 x+y=5 (2)2x+y=32 2x+y=0 (3)3x+2y=5 x+3y=9 (4)6x+5z=
-
x^2+y^2-4*x-5=0 (x-1)^2+(y-2)^2=4 (2-x)^2+(4-y)^2-4*x-5=0 根据
-
①.x2-2x-1 ②.4(x-y+1)+y(y-2x) ③.3x2+5xy-2y2+x+9y-4 ④.x2-5x+3
-
解下列方程组(1){y=1-x,4x-3y=5 (2){2x-y=3,3x+y-1=0 (3)2x+3y=-4,2x-4
-
方程组2x+3y减2=0 4x减9y+1=0,x+1=5(y+2) 3(2x减5)减4(3y+4)=5