1+a+b*(1+a+b-1)=1+1+2*3=8
#denfine MA(x)x*(x-1)main(){int a=1,b=2;printf(“%d\n”,MA(1+a
1个回答
相关问题
-
main() { int x; scanf("%c",x); switch(x) { case,^a^;printf("
-
int func(int x,int y ) { return(x+y) } main() {int a=1,b=2,c
-
#include #include int main(void) { float a,b,c,x,y,z; printf
-
设有宏定义#define ma(x) x*(x-1),且a=1,b=2,则ma(1+a+b)的值为多少
-
(1)-3ma^3+6ma^2+12ma (2)7(a-1)+x(a-1) (3)3(a-b)^2+6(b-a) (4)
-
main() { int x=1,a=0,b=0; switch(x){ case 0:b++; case 1:a++;
-
main() { int x=1,a=0,b=0; switch(x) { case 0:b++; case1:a++;
-
以下程序运行后的输出结果是 main() {int a,b,c; a=1;b=3;c=5; printf(“%d,%d\
-
3.21 以下程序的输出结果是 main() { int a=21,b=11; printf("%d\n",- -a+b
-
有以下程序#includevoid fun(int x){ if(x/2>1)fun(x/2);printf("%d",