Question

(9y的平方-x的平方/x的平方+6xy+9y的平方)/(x-3y/x的平方+3xy)

Answer 1

解

(9y²-x²)/(x²+6xy+9y²)÷(x-3y)/(x²+3xy)

=(3y-x)(3y+x)/(x+3y)²÷(x-3y)/x(x+3y)

=-(x-3y)/(x+3y)×x(x+3y)/(x-3y)

=-x