Question

已知（x+1)的5次方=ax的5次方+bx的4次方+cx的3次方+dx的平方+ex+f,求下列各式的值

Answer 1

(x+1)^5 = x^5 + 5x^4 + 10x^3 + 10x^2 + 5x + 1

a = 1,b = 5,c = 10,d = 10,e = 5,f = 1,

a + b + c + d + e + f = (1+1)^5 = 32

b + c + d + e = 5 + 10 + 10 + 5 = 30

a + c + e = 1 + 10 + 1 = 12