（12x^2y-8xy^2+16xy）/(-3x+2y-4)=-4xy
（12x^2y-8xy^2+16xy）/-3x+2y-4=?
1个回答
相关问题
-
(12x^2y-8xy^2+16xy）/-3x+2y-4=?
-
因式分解1、2x^2(y+2)-3y^3(x-3)-12xy 2、x^3-4xy+4y^2-6x+12y+8
-
因式分解 1、2x^2(y+2)-3y^2(x-3)-12xy 2、x^2-4xy+4y^2-6x+12y+8 3、x^
-
①12x2+8x-3xy-2y ②16a的4次方-b的8次方 ③-3xy-9y²－1／4x² ④12
-
已知x+y=8,xy=12,求(1)x2y+xy2(2)x2-xy+y2(3)x-y
-
x^2-4xy+4y^2=16(x+y)^2-x-y-12=0
-
已知(y+2x)/xy=3/2,求(4x+3xy+2y)/(-4x+8xy-2y)
-
因式分解:12xy^2(y-x)+xy^3(x-y)+4x^2y(x-y)
-
x^2-2xy+y^2=14x^2-4xy+y^2=46x^2-5xy+y^2=0x^2-4xy+3y^2+4x-8y+
-
①若x²-xy=-3,2xy-y²=-8,则2x²+4xy-3y²=