当x>1时,1+﹙1/x﹚=(x+1)/x>0
x/﹙x-1﹚>0
所以(1+1/x)/[(x11)/x]=[(x+1)/x]/[x/(x-1)]=(x+1)(x-1)/x^2=(x^2-1)/x^2=1-1/x^2
因x>1
所以x^2>1
所以0
当x>1时,1+﹙1/x﹚=(x+1)/x>0
x/﹙x-1﹚>0
所以(1+1/x)/[(x11)/x]=[(x+1)/x]/[x/(x-1)]=(x+1)(x-1)/x^2=(x^2-1)/x^2=1-1/x^2
因x>1
所以x^2>1
所以0