Question

(x+1分之x²-1)÷(x²-x分之x²-2x+1)

Answer 1

(x+1分之x²-1)÷(x²-x分之x²-2x+1)=(x+1)(x-1)/(x+1)·x(x-1)/(x-1)²=x(x²-y²分之y(x-y)-x(x+y))÷(x+y之x²+y²)=(xy-y²-x²-xy)/(x+y)(x-y)·(x+y)/(x²+y...