Question

根号下x+y-3+绝对值xxy+x+y-2=0 x+y-3=0 xy+x+y-2=0 x+y=-3 x+y-3=xy+x

Answer 1

√(x+y-3)+|xy+x+y-2|=0 => x+y-3=0,xy+x+y-2=0 => x+y=3,xy=-1

x/y+y/x=(x^2+y^2)/(xy)=[(x+y)^2-2xy]/(xy)=[3^2-2*(-1)]/(-1)=-11