Question

若m.n满足|m+2|+根号下(n-4)=0,分解因式(x²+y²)-(mxy+n)=_____过程

Answer 1

|m+2|+根号下(n-4)=0

则m+2=0,n-4=0

则m=-2,n=4

则(x²+y²)-(mxy+n)=x²+y²+2xy-4=(x+y)²-4=(x+y+2)(x+y-2)