Question

一道分式数学题[1/a-2 + a²-1/(a+2)(a-1)] / (a/a+2)²化简求值,其中

Answer 1

[1/(a-2)+(a²-1)/(a+2)(a-1)]/[a/(a+2)]²

=[1/(a-2)+(a+1)*(a-1)/(a+2)(a-1)]/[a/(a+2)]²

=[1/(a-2)+(a+1)/(a+2)]/[a/(a+2)]²

=[(a+2)+(a+1)(a-2)]/[(a+2)*(a-2)]/[a/(a+2)]²

=a²/[(a+2)*(a-2)]/a²/(a+2)²

=(a+2)/(a-2)

当a=2500是

原式=2502/2498

1251/1249