由AB=6,BG=4√2得,AG=2
AF平分∠BAD得,△ABE是等腰三角形.AB=BE=6,得EG=AG=2,AE=4
CE=AD-BE=9-6=3
由△CEF相似于△DAF得,EF/AF=CF/DF=CE/DA=3/9,得EF=2,CF=3,
CE+CF+EF=8
△CEF周长为8
由AB=6,BG=4√2得,AG=2
AF平分∠BAD得,△ABE是等腰三角形.AB=BE=6,得EG=AG=2,AE=4
CE=AD-BE=9-6=3
由△CEF相似于△DAF得,EF/AF=CF/DF=CE/DA=3/9,得EF=2,CF=3,
CE+CF+EF=8
△CEF周长为8