Question

△ABC中,AB=AC,△ADE中,AD=AE且∠BAC=∠DAE,连BD、CE交于点P.

Answer 1

∠BAC=∠DAE

∠EAC=∠DAB

AB=AC,AD=AE,

△EAC全等于△DAB

∠ACE=∠ABD

∠BPE=∠PBC+∠PCB=∠PBC+∠BCA+∠ACE=∠PBC+∠ABD+∠BCA=∠ABC+∠ACB=180度-∠BAC