Question

用配方法接下列方程:y^2+3y-2=0 x^2-4x+3=0

Answer 1

y²+3y-2=0

y² + 2 * 3/2 * y + (3/2)² = 17/4

(y + 3/2)² = 17/4

y + 3/2 = ±√17/2

y = ±√17/2 - 3/2

y1 = √17/2 - 3/2,y2 = -√17/2 - 3/2

x² - 4x + 3 = 0

x² - 2 * 2 * x + 4 = 1

(x - 2)² = 1

x - 2 = ±1

x = 2 ± 1

x1 = 3, x2 = 1