12题,13题,14题,15题,17题,

1个回答

  • 12题:原式=a2+2ab+b2-a2+2ab-b2=4ab=4*(1/2)=2

    13题:原式=(x-2y)(x+2y)(x-2y)(x+2y)=(x2-4y2)(x2-4y2)=(x2-4y2)2=x4-8x2y2+16y4

    14题:原式=(5的x次方)/(5的y次方)=3/2

    15题:因为P=(-ab3)2=a2b6;所以-P2=-a4b12

    17题:原式=3(x2+2x+1)=3(x+1)2