y''/y'=-1/x
=> ∫y''/y'dx=-∫1/x*dx
=> ∫1/y'*dy'=-∫1/x*dx
=> lny'=-lnx+lnC
=> y'=dy/dx=C/x
=> dy=C/x*dx
=> ∫dy=∫C/x*dx=C∫dlnx
=> y=Clnx+C1
(d^2 y/d^2 x)/(dy/dx)= -(1/x)求特解
∫y''/y'dx=-∫1/x*dx=> ∫1/y'*dy'=-∫1/x*dx=> lny'=-lnx+lnC=> y'="}}}'>
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