谁能提供一些初一的合并同类项例题加答案

1个回答

  • 1去括号

    (1) -(2m-3) (2) n-3(4-2m) (3)16a-8(3b+4c)

    (4)t+2/3(12-9v) (5)-(5m+n)-7(a-3b)

    (6)-1/2(x+y)+1/4(p+q) (7)-8(3a-2ab+4)

    (8)4(m+p)-7(n-2q)

    2化简下列各式:

    (1)-2n-(3n-1) (2)a-(5a-3b)+(2b-a) (3)-3(2s-5)+6s

    (4)1-(2a-1)-(3a+3) (5)3(-ab+2a)-(3a-b)

    (6)14(abc-2a)+3(6a-2abc)

    (7)3(xy-2z)+(-xy+3z)

    答案

    1去括号

    (1) -(2m-3)=-2m+3

    (2) n-3(4-2m)=n-12+6m

    3)16a-8(3b+4c)=16a-24b-32c

    4)t+2/3(12-9v)=t+8-6v

    5)-(5m+n)-7(a-3b)=-5m-n-7a+21b

    6)-1/2(x+y)+1/4(p+q)=-1/2x-1/2y+1/4p+1/4q

    7)-8(3a-2ab+4)=-24a+16ab-32

    8)4(m+p)-7(n-2q)=4m+4p-7n+14q

    2化简下列各式:

    (1)-2n-(3n-1)=-5n+1

    (2)a-(5a-3b)+(2b-a)=-5a+5b

    (3)-3(2s-5)+6s=15

    (4)1-(2a-1)-(3a+3)=-5a-1

    (5)3(-ab+2a)-(3a-b)=3a-3ab+b

    (6)14(abc-2a)+3(6a-2abc) =14abc-28a+18a-6abc=8abc-10a

    (7)3(xy-2z)+(-xy+3z) =3xy-6z-xy+3z=2xy-3z