1.得:y=4/3x z=5/3y 依次代入上式得=155/79
2.得:(a+b+c)(x-y)
3.=xy(x²+y²)=xy[(x+y)²-2xy]=-6(0+6)=36
4.=(2x+y-z)(2x-y+z) 则另一个因式为:2x+y-z
5.(x+12)(x-2)=x²-2x+12x-24=x²+10x-24 则k=10
6=-(b³+2)(b³-2)=-[(b³)²-2²]=4-(b³)²
是不是满意呢
1.得:y=4/3x z=5/3y 依次代入上式得=155/79
2.得:(a+b+c)(x-y)
3.=xy(x²+y²)=xy[(x+y)²-2xy]=-6(0+6)=36
4.=(2x+y-z)(2x-y+z) 则另一个因式为:2x+y-z
5.(x+12)(x-2)=x²-2x+12x-24=x²+10x-24 则k=10
6=-(b³+2)(b³-2)=-[(b³)²-2²]=4-(b³)²
是不是满意呢