由题意知ξ的可能取值是0,1,2,3,
P(ξ=0)=0.4×0.4×0.4=0.064
P(ξ=1)=0.4×0.4×0.6=0.096
P(ξ=2)=0.4×0.6=0.24
P(ξ=3)=0.6,
∴Eξ=1×0.096+2×0.24+3×0.6=2.376
故答案为:2.376
由题意知ξ的可能取值是0,1,2,3,
P(ξ=0)=0.4×0.4×0.4=0.064
P(ξ=1)=0.4×0.4×0.6=0.096
P(ξ=2)=0.4×0.6=0.24
P(ξ=3)=0.6,
∴Eξ=1×0.096+2×0.24+3×0.6=2.376
故答案为:2.376