Question

求直线y=2-x和双曲线x^2-2y^2=4的交点坐标

Answer 1

y=2-x

x^2-2y^2=4

x^2-2(2-x)^2=4

-x^2+8x-8-4=0

x^2-8x+12=0

x=2,或x=6

直线交双曲线于AB两点

Ax=0,Ay=0,Bx=6,By=-4