问一道分式题:已知x/y=2/7,求分式x²﹣3xy﹢2y²/x²﹢2xy﹢y²的值.
5个回答
∵x/y=2/7
∴x=2k y=7k
∴原式=(4k²-42k²+98k²)/(4k²+28k²+49k²)
=60/81
=20/27
相关问题
已知x/y=2/7,求分式x²-3xy+2y²/x²-2xy+y²的值.
已知1/x+1/y=2,求分式3x-7xy+3y/2x-5xy+2y的值
已知1/x-1/y=5,求分式2x+3xy-2y/x-2xy-y的值
已知1/x+1/y=5,求分式2x-3xy+2y/x+2xy+y的值
1.已知1/x-1/y=3,求分式2x+3xy-2y/(x-2xy-y)的值
已知1/x+1/y=3,求分式3x-2xy+3y/x+xy+y的值
已知x-y/xy=2,求分式7x-5xy-7y/5x-5y
分式题,已知:1/x+2/y=3求:(4x-7xy+8y)÷(3x+xy+6y)
已知1/X—1/Y=4,求分式3X+XY—3Y/X—2XY—Y的值.
急@#!#24已知1/x-1/y=3,求分式2x+3xy-2y/x-2xy-y的值