设1/10(x-100)=t,则x-100=10t,x=10t+100
100+1/10(x-100)=200+1/10[x-200-100-1/10(x-100)]
100+t=200+1/10[10t-200-t]
1000+10t=2000+10t-200-t
t=800
x=10t+100=8100
设1/10(x-100)=t,则x-100=10t,x=10t+100
100+1/10(x-100)=200+1/10[x-200-100-1/10(x-100)]
100+t=200+1/10[10t-200-t]
1000+10t=2000+10t-200-t
t=800
x=10t+100=8100