[(-3ab)²×a³+2a³×(-3ab)³×1/2b]÷(3a²b
2个回答
[(-3ab)²×a³+2a³×(-3ab)³×1/2b]÷(3a²b²)²
=[9a^5b^2+a^3b(-3ab)^3]÷9a^4b^4
=ab^-2-3a^2
=a(b^-2-3a)
相关问题
1.若规定a×b=a+b+ab,则-2×3=( ) 1×(2×3)=( )
计算:(-a/b)×(-b^2/2a)^3÷(-ab^4)
计算:(a^2-b^2)÷(a^2+2ab+b^2)×(a^3+b^3)
[1/(a-b)-(a+b)/(a2+ab+b2)+ab/(b3-a3)]×(a3-b3)
化简 (-a)²×a³×(-3b)³-(-3ab)²×(-a)³×b
化简-2/3a²b×(-2ab²c)²×3b³
计算:[﹙ab-2b﹚²×﹙2a﹚²-﹙4ab﹚²]÷[16a×﹙ab﹚²]
a=3 b=2 ab×b=
(a²-2ab+b²)²*²+¹÷(a-b)³×²
根号ab³÷(—3根号2a分之b)×(—3根号2a)