Question

若（x^2）-6x+（y^2）+4y+13=0

Answer 1

(x^2-6x+9)+(y^2+4y+4)=0

(x-3)^2+(y+2)^2=0

因为(x-3)^2大于等于0,(y+2)^2大于等于0,

所以x-3=0

y+2=0

x=3,y=-2