Question

某商场文具专柜以每支a元的价格购进一批英雄牌钢笔

Answer 1

设文具专柜共购进X支钢笔:

(a+2)X=339a+805

X=(339a+805)/(a+2)

=(339a+678+127)/(a+2)

=[339(a+2)+127]/(a+2)

=339+127/(a+2)

X为整数,127/(a+2)最小值=1,a+2=127,a=125(元)

X=339+1=340(支)