-1/2.洛必达.
lim(x→0) (ln cosx)/[ln(1+x^2)] 等于多少?
1个回答
相关问题
-
lim x→0[ln(cosx)]/x^2
-
lim/x-0(cosx)/ln(1+x^2)求极限
-
1、lim ln(1+x+2x^2)+ln(1-x+x^2)/secx-cosx
-
lim(x->0)[cosx-e^(-x^2/2)]/[x^2[x+ln(1-x)]]
-
lim(x→0)[ln(1+x)]/x=lim(x→0)[ln(1+x)]^(1/x)
-
lim(x趋于0)(1-cosx)/[ln(1+x)(e^x-1)]
-
lim(x→0)(1-cosx)[x-ln(1+tanx)]/(sinx)^4
-
x→0时lim(1-cosx/sin2x×ln(1+3x))
-
lim(x->0)[ln(1+x)]/|x|等于什么?
-
lim (cosx)^ln(1/1+x^2)怎么算